Solving Reorganize String in go. Please try yourself first to solve the problem and submit your implementation to LeetCode before looking into solution.

## Problem Description

Given a string S, check if the letters can be rearranged so that two characters that are adjacent to each other are not the same.

If possible, output any possible result. If not possible, return the empty string.

Example 1:

``````Input: S = "aab"
Output: "aba"``````

Example 2:

``````Input: S = "aaab"
Output: ""``````

Note:

S will consist of lowercase letters and have length in range [1, 500].

``````    string reorganizeString(string S) {
vector<int> mp(26);
int n = S.size();
for (char c: S)
++mp[c-'a'];
priority_queue<pair<int, char>> pq;
for (int i = 0; i < 26; ++i) {
if (mp[i] > (n+1)/2) return "";
if (mp[i]) pq.push({mp[i], i+'a'});
}
queue<pair<int, char>> myq;
string ans;
while (!pq.empty() || myq.size() > 1) {
auto cur = myq.front();
myq.pop();
if (cur.first != 0) pq.push(cur);
}
if (!pq.empty()) {
auto cur = pq.top();
pq.pop();
ans += cur.second;
cur.first--;
myq.push(cur);
}
}
return ans;
}``````

See the full details of the problem Reorganize String at LeetCode

Originally posted at: @github.com/halfrost/LeetCode-Go